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Fraction Question

QUESTION REVIEW In this article, I will set some  Fraction Question.  Let see what you got. QUESTION 1.  $ 81 \div 3 \div 2 \div 3 $      2.  $ 81 \div 3 \div \frac{2}{3} $ 3.  $ 81 \div \frac{3}{2} \div 3 $       4.  $ \frac{81}{3} \div 2 \div 3 $ 5.  $ \frac{81}{3} \div \frac{2}{3} $       6.  $ \frac{81}{3} \over \frac{2}{3} $ 7.  $ 1\frac{1}{2}3 $       7.  $ 1\frac{1}{2}3 + 2\frac{3}{4}2 - 1\frac{1}{4} $
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Commutative Law of Addition

TOPIC OVERVIEW In this article, I will explain the use of the Commutative Law of Addition , and suggest a better way of thinking about the topic. Please add your ideas in the comments. THE COMMUTATIVE LAW ("change" the order of the numbers or letters) Over the years, people have found that when we add or multiply, the order of the numbers will  not affect the outcome. " Switching " or " changing " the order of numbers is called " commuting ". When we change the order of the numbers, we have applied the " Commutative Law ". In an addition problem, it is referred to as the " Commutative Law of Addition " such that Addition on the Real Number ( 2, -5, and $ \frac{2}{7} $  )  S , T it is true  that    S + T = T + S THE SUM OF 2 REAL NUMBERS Example Real Numbers 2 & 3 Let make S=2 & T=3 Solution S+T = T + S 2+3 = 3 + 2 5 = 5 Note: - This is the sum of 2 positive real numbers.  S

Like Terms

TOPIC OVERVIEW In this article, I will explain the use of a Like Term, and suggest a better way of thinking about the topic. Please add your ideas in the comments. Like Term : This is a term whose variables are the same. in other words, terms that are "Like" each other. Note: the coefficients (the numbers you multiply by, such as "5" in 5x) can be different. Example 7 x x -2 x Are all  like terms  because the variables are all x (1/3) xy 2 −2 xy 2 6 xy 2 xy 2 /2 Are all  like terms  because the variables are all x Unlike Term :  If they are not like terms, they are called " Unlike Terms ": Unlike Terms Why they are "Unlike Terms" −2 xy −4 y 13 y 2 ←  these are all  unlike terms   (  xy ,  y  and  y 2  are all different) 2 x       2 x 2      2 y       2 xy These are all  Unlike Terms  because the variables and/or their exponents are different. CO

THE USE OF BRACKET IN MATHEMATICS

TOPIC REVIEW In this article, I will explain the use of a bracket, and suggest a better way of thinking about the topic. Please add your ideas in the comments BRACKET A bracket is used to clarify expressions by grouping those term affected by a common operator TYPES OF BRACKET Parenthesis                  (  ) Square Bracket            [  ] Braces                         {  } Angles Bracket           <  > USE OF BRACKET In order to simplify a Mathematical expression, it is frequently necessary to 'remove brackets' this means to rewrite an expression which includes a bracketed term in an equivalent form but without the bracket. for example,   8-(3+2) which is 8-(5) = 8-5 = 3 you can write 8-(3+2) in an equivalent form we will multiply the - sign with what is in the bracket -(3+2) which is -3-2  which rewrite our question to 8-3-2 = 3 either way the result is 3. 8-(3+2) is same as  8-3-2 this operation must be carried out according to certain r

prove to \( 48 \div 2(9+3) \) is 2

Topic Review  The question \( 48 \div 2(9+3) \) has been a war on the internet for years now. I will like you to follow my prove with a pen and note in your hand Maths Is The Study Of Balance You will probably think what does this guy mean my maths is the study of balance. Let take a look at weighing scale Weighing scale Weighing scale is a good example of left-hand side {LHS} and right-hand side {RHS} in our day to day mathematics. it also explains the value at the LHS is equal to the value at the RHS to make it stay balanced. we have \( x^a \times x^b =  x^{ab} \) example \( 2^2 \times 2^3 = 2^{2+3} = 2^5 = 32 \) to bring our answer back to the first step we need to use this \( x^{ab} = x^a \times x^b \) example \( 32 = 2^5 = 2^{2+3} = 2^2 \times 2^3 \) which tells you ether you use the reverse way \( x^a \times x^b =  x^{ab} \) or \( x^{ab} = x^a \times x^b \) you are still use the rule of indices only in the reverse way Word Example I will take you back to y